A) \[_{90}^{233}Th\xrightarrow[{}]{{}}\,_{90}^{233}Pa{{+}_{-2}}{{e}^{0}}\]
B) \[_{90}^{233}Th\xrightarrow[{}]{{}}\,_{91}^{233}Pa{{+}_{-1}}{{e}^{0}}\]
C) \[_{90}^{233}Th\xrightarrow[{}]{{}}\,_{90}^{292}Pa{{+}_{0}}{{e}^{4}}\]
D) \[_{90}^{233}Th\xrightarrow[{}]{{}}\,_{91}^{229}Pa{{+}_{-1}}{{e}^{4}}\]
Correct Answer: B
Solution :
According Soddy-Fajans rule when one\[\beta -\] particle is emitted, the atomic no. increases by 1, but the atomic mass remains same. Hence, the correct equation will be \[_{90}^{233}Th\xrightarrow[{}]{{}}\,_{91}^{233}Pa{{+}_{-1}}{{e}^{0}}\]
You need to login to perform this action.
You will be redirected in
3 sec
