A) 3.48 kJ
B) 3.74 kJ
C) 37.4kJ
D) 34.8kJ
Correct Answer: B
Solution :
Given that: \[n=1\] \[T=300K\] \[R=8.314Joul\,{{K}^{-1}}mo{{l}^{-1}}\] Now by using: KE (kinetic energy) \[=\frac{3}{2}nRT\] \[=\frac{1}{2}\times 8.314\times 300\] \[=3740\text{ }Joule\] \[=3.74kJ\]
You need to login to perform this action.
You will be redirected in
3 sec
