A) \[19.6\times {{10}^{8}}N/{{m}^{2}}\]
B) \[19.6\times {{10}^{-10}}N/{{m}^{2}}\]
C) \[19.6\times {{10}^{10}}N/{{m}^{2}}\]
D) \[19.6\times {{10}^{-8}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
Here: \[\Delta V~=0.1%\text{ }V=0.001\text{ }V,\text{ }h=200\text{ }m,\] \[\rho =1000kg/{{m}^{3}}\] Pressure at the depth h is given by \[\text{p}=h\rho g=200\times 1000\times 9.8\] \[=1.96\times {{10}^{6}}N/{{m}^{2}}\] The Bulk modulus of material of the ball is \[K=\frac{PV}{\Delta V}=\frac{1.96\times {{10}^{6}}\times V}{0.001}\] \[=19.6\times {{10}^{8}}N/{{m}^{2}}\]
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