Manipal Medical Manipal Medical Solved Paper-2003

  • question_answer
    The speed of sound through oxygen at TK is \[\upsilon \text{ }m{{s}^{-1}}\]. As. the temperature becomes 2T and oxygen gas dissociates into atomic oxygen, the speed of sound:

    A)  remains the same

    B)  becomes \[2\upsilon \]

    C)  becomes \[\sqrt{2\upsilon }\]

    D)  none of these

    Correct Answer: B

    Solution :

     The rms velocity of sound in gas is \[{{\upsilon }_{rms(molecules)}}=\sqrt{\frac{\gamma RT}{M}}=\sqrt{\frac{1.44\times RT}{M}}\] ?(1) when the oxygen dissociates, its molecular mass becomes atomic mass, so,\[M=\frac{M}{2}\]and\[T=2T\]given, and\[\gamma =1.66\] \[{{\upsilon }_{rms(atomic)}}=\sqrt{\frac{1.66\times R\times 2T}{M/2}}\] \[=\sqrt{\frac{1.66\times R\times 2T\times 2}{M}}\] ?.(2) From equations (1) and (2) \[\frac{{{\upsilon }_{rms(atomic)}}}{{{\upsilon }_{rms(molecular)}}}=\sqrt{\frac{1.66\times R\times 2R\times 2}{M}}\] Hence, \[{{\upsilon }_{rms(atomic)}}=2.18\,{{\upsilon }_{rms(molecular)}}\] \[\approx 2\,{{\upsilon }_{rms(molecular)}}\]


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