A) \[4:1\]
B) \[2:1\]
C) \[1:2\]
D) \[1:1\]
Correct Answer: A
Solution :
The gas equation is \[PV=nRT\] Suppose\[{{n}_{1}}\]and\[{{n}_{2}}\]moles of the gas be in jar A and jar B respectively Then \[{{P}_{2}}{{V}_{2}}={{n}_{2}}R{{T}_{2}}\] \[\frac{{{n}_{2}}}{{{n}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}{{T}_{1}}}{{{P}_{1}}{{V}_{1}}{{T}_{2}}}\] For jar A \[{{P}_{1}}=P\] \[{{V}_{1}}=V\] For jar B \[{{P}_{2}}=2P\] \[{{V}_{2}}=V/4\] \[{{T}_{2}}=2T\] \[\frac{{{n}_{2}}}{{{n}_{1}}}=\frac{2PVT}{PV\times 4\times 2T}\] \[=\frac{1}{4}\] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{4}{1}\]
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