A) \[FeC{{l}_{3}}\]
B) \[AlC{{l}_{3}}\]
C) \[SnC{{l}_{4}}\]
D) \[AlC{{l}_{3}}.6{{H}_{2}}O\]
Correct Answer: D
Solution :
\[AlC{{l}_{3}}\]is Lewis acid because it has\[s{{p}^{2}}\]hybridisation it can easily accept electrons but by adding 6 water molecules its vacant orbitals filled and they are not available for accepting electrons.
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