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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    \[{{N}_{2(g)}}+3{{H}_{2(g)}}\xrightarrow[{}]{{}}2N{{H}_{3(g)}}\]. For the above reaction the correct statement is:

    A)  \[\Delta H<\Delta E\]         

    B)  \[\Delta H=\Delta E\]

    C)  \[\Delta H>\Delta E\]         

    D)  none of these

    Correct Answer: A

    Solution :

     \[\underset{1\,mol}{\mathop{{{N}_{2(g)}}}}\,+\underset{3\,mol}{\mathop{3{{H}_{2}}(g)}}\,-\underset{2\,mol}{\mathop{2N{{H}_{3(g)}}}}\,\] We know that \[\Delta H=\Delta E+P\Delta V=\Delta E+\Delta nRT\] Here, \[\Delta n=2-(1+3)=-2\] Therefore, \[\Delta H<\Delta E\]


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