A) keto-enol isomerism
B) geometrical isomerism
C) enantiomerism
D) diasterioisomerism
Correct Answer: A
Solution :
Ethyl acetoacetate represents keto-enol isomerism. \[\underset{Keto\,form}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ |\,\,| \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,HCOO{{C}_{2}}{{H}_{5}}\] \[\underset{Enolic\text{ }form}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,}}\,=CHCOO{{C}_{2}}{{H}_{5}}\]
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