A) BHC
B) hexachlorobenzene
C) chlorobenzene
D) triphenyl phosphate
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}OH+PC{{l}_{5}}\xrightarrow[{}]{{}}\underset{Chlorobenzene}{\mathop{{{C}_{6}}{{H}_{5}}Cl}}\,+POC{{l}_{3}}\] \[+3HCl\] \[3{{C}_{6}}{{H}_{5}}OH+POC{{l}_{3}}\xrightarrow[{}]{{}}\underset{Triphenyl\text{ }phosphate}{\mathop{{{({{C}_{6}}{{H}_{5}})}_{3}}P{{O}_{4}}}}\,\] \[+3HCl\]
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