Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    The work function for aluminium surface is 4.2 eV. The cutoff wavelength for photoelectric effect is:

    A)  \[1000\overset{o}{\mathop{\text{A}}}\,\]           

    B)  \[2000\overset{o}{\mathop{\text{A}}}\,\]

    C)  \[2955\overset{o}{\mathop{\text{A}}}\,\]           

    D)  \[4200\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

     Using the relation \[W=\frac{hc}{\lambda }\]so, \[\lambda =\frac{hc}{W}\] Or \[\lambda =\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.2\times 1.6\times {{10}^{-19}}}=2955\overset{o}{\mathop{\text{A}}}\,\]


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