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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    From a point charge, there is a fixed point A. At A, there is an electric field of 500 volt/meter and potential difference of 3000 V. Distance between the point charge and A is:

    A)  24m            

    B)  16m

    C)  12m           

    D)  6m

    Correct Answer: D

    Solution :

     Here: Electric field \[E=500\text{ }V/m\] Potential difference\[V=3000\text{ }V\] Electric field E is given by \[E=\frac{V}{d}\] \[500=\frac{3000}{d}\] so \[d=\frac{3000}{500}=6\,m\]


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