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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    A prism has a refracting angle\[60{}^\circ \]. A ray of given monochromatic light suffers minimum deviation of \[38{}^\circ \] in passing through prism refractive index of the material of prism is:

    A)  1.5094            

    B)  1.3056

    C)  0.7849            

    D)  2.425

    Correct Answer: A

    Solution :

     Here: Refracting angle\[A=60{}^\circ ,\]minimum deviation\[\delta m=38{}^\circ \]The refractive index is given by the formula \[R.I.=\frac{\sin \frac{A+\delta m}{2}}{\sin \frac{A}{2}}=\frac{\sin \frac{60{}^\circ +38{}^\circ }{2}}{\sin \frac{60{}^\circ }{2}}\] \[=\frac{\sin 49{}^\circ }{\sin 30{}^\circ }=\frac{0.7547}{0.5}=1.5094\]


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