A) \[{{10}^{-17}}{{\mu }_{0}}\]
B) \[{{10}^{-11}}{{\mu }_{0}}\]
C) \[{{10}^{-7}}{{\mu }_{0}}\]
D) \[{{10}^{-3}}{{\mu }_{0}}\]
Correct Answer: A
Solution :
Here: Charge on particle \[ne=100\text{ }e=100\times 1.6\times {{10}^{-19}}C\] \[=1.6\times {{10}^{-17}}C\] Radius of circular path \[(r)=0.8\text{ }m\] Time period T = 1 rotation/sec The current associated with the particle is \[i=\frac{charge}{time}=\frac{1.6\times {{10}^{-17}}}{1}\] Hence, magnetic field produced at the centre of the coil is given by \[B={{\mu }_{0}}\times \frac{i}{2r}={{\mu }_{0}}\times \frac{1.6\times {{10}^{-17}}}{2\times 0.8}={{10}^{-17}}{{\mu }_{0}}\]
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