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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    The efficiency of a Cannot engine operating with reservoir temperature of \[100{}^\circ C\] and\[-23{}^\circ C\]will be:

    A)  \[\frac{100-23}{373}\]

    B)  \[\frac{100+23}{373}\]

    C)  \[\frac{100+23}{100}\]

    D)  \[\frac{100-23}{100}\]

    Correct Answer: B

    Solution :

     Using the relation for efficiency of Carnots engine \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{373-250}{373}\] \[=\frac{123}{373}=\frac{100+23}{373}\]


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