Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    At room temperature, the rms velocity of the molecules of a certain diatomic gas is found to be 1930 m/s. Then the gas will be:

    A)  \[C{{l}_{2}}\]            

    B)  \[{{O}_{2}}\]

    C)  \[{{F}_{2}}\]               

    D)  \[{{H}_{2}}\]

    Correct Answer: D

    Solution :

     Rms velocity of molecules \[{{\upsilon }_{rms}}=1930m/s\] It is known that room temperature is \[T=27{}^\circ C=300K\] Molar mass for hydrogen \[M=0.00202\text{ }kg/mol\] rms velocity of a diatomic gas is \[{{\upsilon }_{rms}}=\sqrt{\frac{3RT}{M}}=\sqrt{\frac{3\times 8.31\times 300}{0.00202}}\] \[=1924m/s\] \[\approx 1930m/s\] Hence, the gas is hydrogen (where R is gas constant\[=8.31\text{ }J/mol\text{ }K\])


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