A) \[1.1\,\Omega \]
B) \[2.2\,\Omega \]
C) \[0.5\,\Omega \]
D) \[5\,\Omega \]
Correct Answer: A
Solution :
Here: Voltage of battery \[V=50\text{ }volt\] External resistance\[R=10\text{ }\Omega \]. The current \[i=4.5\text{ }A\] The current is given by, \[i=\frac{V}{R+r}\] Or \[r=\frac{V-iR}{i}\] \[=\frac{50-(10\times 4.5)}{4.5}=\frac{5}{4.5}\] \[=1.1\,\Omega \]
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