Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    Water stands upto a height h behind the vertical wall of a dam. If width of the dam be &, then the net horizontal force pushing the dam down by the stream will be (\[\rho \]is the density of water):

    A)  \[\frac{{{h}^{2}}b\rho g}{2}\]

    B)  \[\frac{{{h}^{2}}{{b}^{2}}\rho g}{4}\]

    C)  \[2hb\rho g\]

    D)  \[\frac{{{h}^{2}}b\rho g}{4}\]

    Correct Answer: A

    Solution :

     Here: Height of water level \[=h\] Width of dam\[=b,\]density -of water\[=\rho \] The force is given by, \[F=pressure\times area\] Or \[F=\frac{h\rho g}{2}\times hb\] Hence, \[F=\frac{{{h}^{2}}b\rho g}{2}\]


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