A) \[112\text{ }ml\]
B) \[224\text{ }ml\]
C) \[56\,ml\]
D) \[336\text{ }ml\]
Correct Answer: B
Solution :
We know that \[\underset{2\times 34\,g}{\mathop{2{{H}_{2}}{{O}_{2}}}}\,\xrightarrow[{}]{{}}2{{H}_{2}}O+\underset{22400\,ml}{\mathop{{{O}_{2}}}}\,\] \[\because \]\[2\times 34\,gm=68\,gm\]of\[{{H}_{2}}{{O}_{2}}\]liberates \[\therefore \]0.68 gm of\[{{H}_{2}}{{O}_{2}}\]liberates \[=\frac{0.68\times 22400}{68}=224\,ml\]
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