A) 3.6 V
B) 10.2 V
C) 3.4 V
D) 13.6 V
Correct Answer: B
Solution :
Minimum excitation energy \[\Delta {{E}_{1}}=Rhc\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)\] \[=13.6\times \frac{3}{4}=10.2\,eV\] Therefore, minimum excitations potential is \[=10.2\text{ }V\]
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