Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    The potential difference between the cathode and the target in a Coolidge tube is 100 kV. The minimum wavelength of the X-ray emitted by the tube is:

    A)  \[0.66\overset{o}{\mathop{\text{A}}}\,\]          

    B)  \[938\overset{o}{\mathop{\text{A}}}\,\]

    C)  \[0.246\overset{o}{\mathop{\text{A}}}\,\]         

    D)  \[0.123\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

     Here: Potential difference \[V=100\text{ }kV\]                        \[=100\times {{10}^{3}}V\] The minimum wavelength of the X-rays is \[{{\lambda }_{\min }}=\frac{hc}{eV}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 100\times {{10}^{3}}}\] \[=0.123\times {{10}^{-10}}\] \[=0.123\overset{o}{\mathop{\text{A}}}\,\]


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