A) 10 V
B) 30 V
C) 45 V
D) 90 V
Correct Answer: A
Solution :
Magnetic flux \[\phi =5{{t}^{2}}+3t+16\] Then the induced emf as given by \[E=\frac{d\phi }{dt}=\frac{d}{dt}(5{{t}^{2}}+3t+16)\] \[E=10t+3\] ...(1) When\[t=3\]from above Eq. (1), we get \[{{E}_{3}}=(10\times 3)+3\] \[{{E}_{3}}=33\,V\] ?.(2) When\[t=4,\]from Eq. (1), we get \[{{E}_{4}}=10\times 4+3=43V\] ...(3) Hence, emf induced in fourth second is \[={{E}_{4}}-{{E}_{3}}=43-33=10V\] [From Eqs. (2) and (3)]
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