Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    A packet is dropped from a balloon which is going upwards with the velocity 12 m/s, the velocity of the packet after 2 seconds will be:

    A)  \[-12\text{ }m/s\]          

    B)  12 m/s

    C)  \[-7.6\text{ }m/s\]      

    D)  7.6 m/s

    Correct Answer: C

    Solution :

     Given, Velocity of balloon \[u=12\text{ }m/s\] Time                        \[t=2\text{ }sec\] when the packet is released from the balloon it aquires the velocity of balloon it means initial velocity of the packet \[=12\text{ }m/s\] Hence, velocity after 2 sec is given by, \[v=u+at\] \[=12+(-9.8)\times 2\] \[=12-19.6=-7.6\text{ }m/s\] (minus sign is due to the motion is in opposite direction)


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