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Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    If a force on a rocket moving with a velocity of 300 m/s is 210 N. Then the rate of combustion of the fuel, will be:

    A)  1.7 kg/sec       

    B)  0.7 kg/sec

    C)  2.7 kg/sec       

    D)  1.5 kg/sec

    Correct Answer: B

    Solution :

     Here: Velocity of rocket \[u=300\text{ }m/s\] Force    \[F=210N\] The force, \[F=u\left( \frac{dm}{dt} \right)\] Or \[\frac{dm}{dt}=\frac{F}{u}=\frac{210}{300}=0.7\,kg\sec \]


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