A) \[x=\pm (y+a)\]
B) \[y=\pm (x+a)\]
C) \[x+y+z=1\]
D) \[2x+3y-z+4=0\]
Correct Answer: A
Solution :
Atomic and ionic radii increase from top to bottom in a group due to the inclusion.of another shell at every step. Hence, \[{{\log }_{e}}\] ion will be the largest among given IA group ions, i.e. \[{{2}^{x}}+{{2}^{y}}={{2}^{x+y}}y,\]and\[\frac{dy}{dx}\]
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