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Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    \[{{x}^{2}}-4x+4{{y}^{2}}=12\]is heated in 1L vessel till equilibrium state is established.\[\frac{\sqrt{3}}{2}\] In  equilibrium  state,  50% \[\frac{2}{\sqrt{3}}\] was dissociated, equilibrium constant will be (molecular wt. of \[\sqrt{3}\])

    A)  0.1                                        

    B) 0.4

    C) 0.3                                         

    D) 0.2

    Correct Answer: B

    Solution :

    \[y={{\log }_{e}}(x)+C\] Molar concentration of \[y={{({{\log }_{e}}x)}^{2}}+C\] In equilibrium state, when it 50% dissociates \[y=\pm \sqrt{{{\log }_{e}}x{{)}^{2}}+2C}\] \[xy={{x}^{y}}+C\] Now, from\[\frac{4}{{{100}^{3}}}\] \[\frac{3}{{{50}^{3}}}\]


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