A) \[\int_{1}^{4}{{{\log }_{e}}[x]dx}\]
B) \[{{\log }_{e}}2\]
C) \[{{\log }_{e}}3\]
D) \[{{\log }_{e}}6\]
Correct Answer: B
Solution :
\[\left. \left. +{{\cos }^{-1}}\frac{\sqrt{12}}{4}+{{\sec }^{-1}}\sqrt{2} \right) \right\}\] This order can be easily explained on the basis of the tendaney of the halogen atom to back donate its lone pair of electrones to empty p-orbital of the boron atom through \[\frac{\pi }{4}\] bonding.
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