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Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    The enthalpy of combustion of carbon and carbon  monoxide   are  - 393.5   and 283 kJ/mol respectively. The enthalpy of formation of carbon monoxide per mole is

    A) 110.5 kJ               

    B) 676.5 kJ

    C) -676,5 kJ              

    D) -110.5kJ

    Correct Answer: D

    Solution :

    I\[f(x)=\sqrt{{{x}^{2}}-4,}a=2\] II:\[\sqrt{5}\] \[\sqrt{3}\] On substracting II from I III:\[\sqrt{3}+1\] \[n(n+1)d\] This equation III also represents formation of mole of CO and thus enthalpy of formation of \[\frac{n(n+1)d}{2n+1}\]is -110.5 kJ/mol


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