A) maximum in radius
B) maximum in volume
C) maximum in density
D) equal in radius, volume and density
Correct Answer: B
Solution :
Let R be the radius of sphere, V its volume and \[HCl{{O}_{4}}\] its density. Then,\[A\xrightarrow[{}]{{}}B;{{k}_{1}}={{10}^{10}}{{e}^{-20,000/T}}\]and percentage change in radius \[C\xrightarrow[{}]{{}}D;{{k}_{2}}={{10}^{12}}{{e}^{-24,606/T}}\] ...(i) Now, \[{{k}_{1}}\] \[{{k}_{2}}\] \[CaC{{l}_{2}}\] Percentage increase in volume \[C{{s}^{+}}\] ?(ii) Again,\[C{{l}^{-}}\] \[9.2g{{N}_{2}}{{O}_{4}}\]\[{{N}_{2}}{{O}_{4}}(g)2N{{O}_{2}}(g)\] \[{{N}_{2}}{{O}_{4}}\] Percentage change in density \[{{N}_{2}}{{O}_{4}}=92\] ?(iii) From Eqs. (i), (ii) and (iii), we see that the percentage change is maximum in volume.
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