A) \[x=\frac{1}{2}\]
B) \[x=\frac{1}{2}\]
C) \[\underset{x\to {{(1/2)}^{+}}}{\mathop{\lim }}\,f(x)=2\]
D) \[\underset{x\to {{(1/2)}^{-}}}{\mathop{\lim }}\,f(x)=1\]
Correct Answer: A
Solution :
According to Einstein's photoelectric equation, \[1.6\times {{10}^{-6}}N\] If \[\theta \ne {{0}^{o}},\] is retarding or stopping potential and Vy is the threshold frequency, then the above equation becomes \[\text{m}{{\text{s}}^{-1}}\] \[15(\sqrt{3}-1)s\] \[15(\sqrt{3}+1)s\] Hence, \[7.5(\sqrt{3}-1)s\] \[7.5(\sqrt{3}+1)s\] Therefore, required frequency, \[\text{ }\!\!\beta\!\!\text{ }\] \[5\times {{10}^{-2}}m,\] \[3\times {{10}^{-5}}m.\] \[1\times {{10}^{-3}}m.\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\] \[Li<Na<K<Rb\]
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