A) \[{{N}_{2}}{{O}_{4}}(g)2N{{O}_{2}}(g)\]
B) \[{{N}_{2}}{{O}_{4}}\]
C) \[{{N}_{2}}{{O}_{4}}=92\]
D) \[{{T}^{2}}{{\left[ \frac{\delta (G/T)}{\delta T} \right]}_{p}}\]
Correct Answer: D
Solution :
When a galvanometer is connected to the shunt resistance, then we have potential drop across the galvanometer = potential drop across the shunt i.e. \[x=\frac{1}{2}\] ...(i) Here, i = current through the galvanometer G = resistance of the galvanometer \[\underset{x\to {{(1/2)}^{+}}}{\mathop{\lim }}\,f(x)=2\] = current through the shunt resistance S = shunt resistance From Eq. (i), we have the part of the total current that flows through the galvanometer is\[\underset{x\to {{(1/2)}^{-}}}{\mathop{\lim }}\,f(x)=1\] Substituting, \[f(x)=\min \{1,{{x}^{2}},{{x}^{3}}\},\]we get\[{{x}_{n}}=\cos \frac{\pi }{{{3}^{n}}}+i\sin \frac{\pi }{{{3}^{n}}},\]
You need to login to perform this action.
You will be redirected in
3 sec
