A) \[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{{{(\sec x+\tan x)}^{9/2}}}dx}\]
B) \[-\frac{1}{{{(\sec x+\tan x)}^{11/2}}}\left\{ \frac{1}{11}-\frac{1}{7}{{(\sec x+\tan x)}^{2}} \right\}+K\]
C) \[\frac{1}{{{(\sec x+\tan x)}^{11/2}}}\left\{ \frac{1}{11}-\frac{1}{7}{{(\sec x+\tan x)}^{2}} \right\}+K\]
D) \[-\frac{1}{{{(\sec x+\tan x)}^{11/2}}}\left\{ \frac{1}{11}+\frac{1}{7}(\sec x+\tan x) \right\}+K\]
Correct Answer: B
Solution :
Radius of a nucleus is given by \[200\mu F\] (where,\[{{E}_{2}}\]) \[{{r}_{1}}\] Here, A is the mass number and mass of the uranium nucleus will be \[{{r}_{2}}\] mass of proton\[{{E}_{2}}{{r}_{1}}>{{E}_{1}}(R+{{r}_{2}})\] \[{{E}_{1}}{{r}_{2}}<{{E}_{2}}({{r}_{1}}+R)\]Density\[{{E}_{2}}{{r}_{2}}<E(R+{{r}_{2}})\] \[{{E}_{1}}{{r}_{1}}>{{E}_{2}}({{r}_{1}}+R)\] \[{{n}_{1}}\]\[{{n}_{1}}({{n}_{1}}>{{n}_{2}}).\]
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