Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    The specific heat at constant volume for the mono atomic argon is 0.075 kcal/kg-K, whereas its gram molecular specific heat is \[\frac{5}{2}\] cal/mol K. The mass of the carbon  atom is

    A) \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left\{ \frac{a_{1}^{1/x}+a_{2}^{1/x}+...+a_{n}^{1/x}}{n} \right\}}^{nx}},\]                             

    B) \[{{a}_{1}}+{{a}_{2}}+...+{{a}_{n}}\]

    C) \[{{e}^{{{a}_{1}}+{{a}_{2}}+...+{{a}_{n}}}}\]                        

    D) \[\frac{{{a}_{1}}+{{a}_{2}}+...+{{a}_{n}}}{n}\]

    Correct Answer: A

    Solution :

     Molar specific heat = Molecular weight x gram specific heat. \[\pi \] \[\pi \] \[^{\text{235}}\text{U}\] \[36.5\times {{10}^{3}}kg\]Molecular weight of argon,\[36\times {{10}^{2}}kg\]i.e. mass of \[39.5\times {{10}^{3}}kg\] atom = 39.7 g Therefore, mass of single atom \[38.2\times {{10}^{3}}kg\]\[10\mu F\]


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