Manipal Engineering Manipal Engineering Solved Paper-2015

  • question_answer
    The total number of natural numbers of 6 digits that can be made with digits 1, 2, 3, 4, if all digits are to appear in the same number at least once, is

    A) 1560                      

    B) 840

    C) 1080                      

    D) 480

    Correct Answer: A

    Solution :

     There can be 2 types of numbers. (i) Any one of the digits 1,2,3,4 repeats thrice and .the remaining digits only once i.e., of the type 1, 2, 3, 4, 4, 4. (ii) Any two of the digits 1,2,3,4 repeat twice and the remaining two only once i.e.,of the type 1, 2, 3, 3, 4, 4. Number of numbers of the type 1 2 3 4 4 4 \[=\frac{6!}{3!}{{\times }^{4}}{{C}_{1}}=480\] Number of numbers of the type 1 2 3 3 4 4 \[=\frac{6!}{2!2!}{{\times }^{4}}{{C}_{2}}=1080\] So, the required number = 480 + 1080 = 1560


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