A) \[-\frac{2}{{{x}^{2}}}+\frac{8}{{{(r-x)}^{2}}}=0\]
B) \[\Rightarrow \]
C) 0
D) \[\frac{x}{r-x}=\sqrt{\frac{2}{8}}=\frac{1}{2}\Rightarrow x=\frac{r}{3}\]
Correct Answer: C
Solution :
We have, \[y-3z+6=0\]\[3y-2+6=0\] \[y+3z+6=0\]\[3y-2z+6=0\] \[a=2\hat{i}=2\hat{j}-2\hat{k}\]\[b=\hat{i}+\hat{j}\]
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