A) \[\frac{x}{-2}+\frac{y}{1}=-1\]
B) \[\frac{x}{2}+\frac{y}{3}=1\]
C) \[\frac{x}{2}+\frac{y}{1}=1\]
D) \[({{a}^{2}},-{{b}^{2}})\]
Correct Answer: B
Solution :
The mean of the series a, a + d, a + 2d,.. .a + 2nd is \[\frac{\sqrt{2}}{3}\] \[\frac{2}{3}\]\[\frac{1}{3}\] \[2x-3y-4=0\]Mean deviation from mean, \[x+y=1,\] \[\sqrt{2}\]\[5\sqrt{2}\] \[\frac{1}{\sqrt{2}}\]\[\frac{1}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
