Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    A circular disc of radius \[m=\frac{3}{2}\]is cut from a circular disc of radius R and mass 9M as shown. Then, moment of inertia of remaining disc about 'O perpendicular to the plane of the disc is

    A) \[m=\frac{2}{3}\]

    B) \[{{x}^{2}}+{{y}^{2}}-x=0\]

    C) \[4{{x}^{2}}+2{{y}^{2}}-9y=0\]                  

    D) \[2{{x}^{2}}+4{{y}^{2}}-9x=0\]

    Correct Answer: A

    Solution :

    \[N{{O}_{2}}(g)\]


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