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Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    \[|y+x|\le 1,\]is the time period of simple pendulum. The point of suspension moves vertically upwards according to \[|y-x|\le 1\]where \[2{{x}^{2}}+2{{y}^{2}}=1\]New time period is \[\left( 2+\frac{\pi }{2} \right)\] then \[\left( 2-\frac{\pi }{2} \right)\]

    A)  4/5                       

    B) 6/5

    C)  5/6                       

    D) 1

    Correct Answer: B

    Solution :

    Acceleration of the point of suspension \[CC{{l}_{4}},C{{F}_{4}},C{{H}_{4}}\] \[C{{H}_{4}},C{{F}_{4}},CC{{l}_{4}}\]and\[C{{F}_{4}}CC{{l}_{4}},CC{{l}_{4}}\] \[C{{F}_{4}},C{{H}_{1}},CC{{l}_{4}}\]


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