A) 0.788 MeV
B) 7,88 MeV
C) 126.15MeV
D) 788 MeV
Correct Answer: D
Solution :
Radius of each nucleus \[\frac{R}{3}\]= 4.8m Distance between two nuclei (r) = 2R So, potential energy \[4M{{R}^{2}}\] \[9M{{R}^{2}}\]
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