Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    The de-Broglie wavelength of a neutron at 27°C is \[\sqrt{ab}\]. What will be its wavelength at 927° C?                  

    A) \[\sqrt{2ab}\]                                   

    B) \[{{\cos }^{-1}}\{\cos 2{{\cot }^{-1}}(\sqrt{2}-1)\}\]

    C) \[\sqrt{2}-1\]                                    

    D) \[\frac{\pi }{4}\]

    Correct Answer: A

    Solution :

    \[{{C}_{1}}=2\mu F\] \[{{R}_{2}}=2\Omega \]\[{{C}_{2}}=4\mu F\]


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