A) \[=kf(x)f(y),\]
B) 1 : 2
C) \[{{\tan }^{-1}}\left( \frac{a}{x} \right)+{{\tan }^{-1}}\left( \frac{b}{x} \right)=\frac{\pi }{2},\]
D) 3 : 2
Correct Answer: A
Solution :
\[\lambda ,\]for both rods K,A and \[\upsilon \] are same \[3\lambda /4\]\[v{{(3/4)}^{1/2}}\] so\[v{{(4/3)}^{1/2}}\]
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