A) \[\Rightarrow \]
B) \[\int_{{}}^{{}}{dv}=k\int_{{}}^{{}}{tdt}\Rightarrow v=\frac{k{{t}^{2}}}{2}\]
C) \[t=\frac{u\sin \theta }{g}=3\]
D) \[\therefore \]
Correct Answer: D
Solution :
Valence electron in A = 3 Valence electron in B = 6 Thus, A is electropositive and 8 is electronegative. A can lose three electrons and B can gain two electrons to attain stable configuration. Thus, A exists as \[\pm 2\] and B as \[\tan \frac{\alpha }{2},\] thus, compound is \[\tan \frac{\beta }{2}\]
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