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Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    Solid \[\left[ {{(LC)}^{2}}\left( \frac{R}{L} \right) \right]={{[{{T}^{2}}]}^{2}}[{{T}^{-1}}]=[{{T}^{3}}].\] is

    A) ionic                      

    B) covalent

    C) coordinate covalent 

    D) metallic

    Correct Answer: A

    Solution :

    Solid \[{{\left( {{x}^{2}}+\frac{1}{{{x}^{2}}}+2 \right)}^{n}}\]is ionic. X-ray diffraction shows that solid \[{{y}^{2}}=4x\] exists as \[{{x}^{2}}=-8y\] (nitronium nitrate).


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