A) 12.4
B) 1.7
C) 2.2
D) 10.9
Correct Answer: D
Solution :
m mol of\[{{x}^{2}}+x-2=0\] \[1,\omega ,{{\omega }^{2}},...{{\omega }^{n-1}}\] m mol of \[n,{{n}^{th}}\]\[(9-\omega ).(9-{{\omega }^{2}})...(9-{{\omega }^{n-1}})\] m mol of \[\frac{{{9}^{n}}+1}{8}\](left) after neutralisation =0.2 \[{{9}^{n}}-1\] pOH = 3.15 and pH = 10.85
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