Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    Raw milk sours in about 4 h at 27°C, but in about 48 h in a refrigerator at 17°C. What is the activation energy for souring of milk?

    A) 78.3 \[=Dyne\times c{{m}^{4}}\]              

    B) 46.21 \[[{{C}^{2}}LR]=\left[ {{C}^{2}}{{L}^{2}}\frac{R}{L} \right]=\left[ {{(CL)}^{2}}\left( \frac{R}{L} \right) \right]\]

    C) 23.5 \[f=\frac{1}{2\pi }\frac{1}{\sqrt{LC}}.\]        

    D) 80.8 \[[{{T}^{2}}].\]

    Correct Answer: A

    Solution :

    \[\beta ={{a}^{3}}+{{a}^{5}}+{{a}^{6}},\] \[{{x}^{2}}-x+2=0\] \[{{x}^{2}}+2x+2=0\]\[{{x}^{2}}+x+2=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner