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Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    A certain radioactive isotope \[\Rightarrow \] (half-life = 10 days) decays to give \[[a]=[p][{{V}^{2}}]=[M{{L}^{-1}}{{T}^{-2}}][{{L}^{6}}]=[M{{L}^{5}}{{T}^{-2}}]\]If 1.0 g of X is   kept in a sealed vessel find the volume of He accumulated at STP in 20 days. Molar mass of \[a=gm\times c{{m}^{5}}\times {{s}^{-2}}\]

    A) 22.40 mL             

    B) 33.40 mL

    C) 55.40 mL             

    D)  66.40 mL

    Correct Answer: D

    Solution :

    Mass of X decay =0.75 g Moles of X decayed \[\text{ }\!\!\pi\!\!\text{ -}\] = moles of He formed \[\text{ }\!\!\pi\!\!\text{ -}\]of He at \[a=\cos \frac{2\pi }{7}+i\sin \frac{2\pi }{7},\]\[\alpha =a+{{a}^{2}}+{{a}^{4}}\]


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