A) \[c<d<a<b\]
B) \[c<d<b<a\]
C) \[a<b<c<d\]
D) \[d<c<a<b\]
Correct Answer: B
Solution :
Greater the number of ions, greater the conduction hence, order of increasing conductivity is \[c<d<b<a\] (a)\[[Pt{{(N{{H}_{3}})}_{6}}]C{{l}_{4}}{{[Pt{{(N{{H}_{3}})}_{6}}]}^{4+}}\] \[+4C{{l}^{-}}=5\]ions (b)\[[Cr{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}[Cr{{(N{{H}_{3}})}_{6}}]+3C{{l}^{-}}=4\]ions (c)\[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]\] \[+C{{l}^{-}}=2\]ions (d)\[{{K}_{2}}[PtC{{l}_{6}}]2K+{{[PtC{{l}_{6}}]}^{2-}}=3\]ions
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