Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    Consider the following reaction in an aqueous solution                 \[{{I}^{-}}(aq)+C{{l}^{-}}\to I{{O}^{-}}(aq)+C{{l}^{-}}(aq)\] and the following initial concentration and initial rate data for this reaction.
    Exp. No \[[{{l}^{-}}]M\] \[[O{{C}^{-}}]M\] Initial rate\[M{{s}^{-1}}\]
    1. 2. 3. 4. 0.1000 0.2000 0.3000 0.3000 0.0500 0.0500 0.0100 0.0200 \[3.05\times {{10}^{-4}}\] \[6.10\times {{10}^{-4}}\] \[1.83\times {{10}^{-4}}\] \[3.66\times {{10}^{-4}}\]
    Which of the following is the correct rate law for this reaction?

    A)  Rate\[=k{{[{{l}^{-}}]}^{2}}[OC{{l}^{-}}]\]

    B) Rate\[=k[OC{{l}^{-}}]\]

    C) Rate\[=k{{[{{l}^{-}}]}^{2}}\]

    D) Rate\[=k[{{l}^{-}}][OC{{l}^{-}}]\]

    Correct Answer: D

    Solution :

    From experiment no -3 and 4, doubling\[[OC{{l}^{-}}]\]doubles the rate;\[i.e.,\]order with respect to\[OC{{l}^{-}}\]is one. Also, from experiment no 1 and 2, doubles the concentration of\[{{l}^{-}}\]double the rate, i.e. order with respect to\[{{l}^{-}}\]is also one. \[rate=k[{{l}^{-}}][OC{{l}^{-}}]\]


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