Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    Two similar coils are kept mutually perpendicular such that their centres coincide. At the centre, find the ratio of the magnetic field due to one coil and the resultant magnetic field through both coils, if the same current is flown

    A) \[1:\sqrt{2}\]                    

    B) \[1:2\]

    C) \[1:3\]                  

    D)        \[\sqrt{3}:1\]

    Correct Answer: A

    Solution :

    Where the two coils are kept perpendicular to each other than resultant field in one coil is directed along the axis of coil and the other downwards, hence resultant field is                 \[B=\sqrt{{{B}^{2}}+{{B}^{2}}}=\sqrt{2}B\] Ratio of magnetic field due to one coil and resultant is                               \[\frac{B}{B\sqrt{2}}=\frac{1}{\sqrt{2}}\]


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