A) \[C{{H}_{3}}C{{H}_{2}}N{{O}_{2}}\]
B) \[{{(C{{H}_{3}})}_{2}}-CHN{{O}_{2}}\]
C) \[{{(C{{H}_{3}})}_{3}}CN{{O}_{2}}\]
D)
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}N{{O}_{2}}\xrightarrow{HN{{O}_{2}}}\,C{{H}_{3}}\underset{\begin{smallmatrix} \\ blue\,\,(nutrioc\,acid) \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ \,\,\,\,\,\,\,\,\,\,N-OH \end{smallmatrix}}{\mathop{N}}\,{{O}_{2}}}}\,\] \[\xrightarrow{NaOH}\,C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ NONa \\ red \end{smallmatrix}}{\mathop{C}}\,-N{{O}_{2}}\] (b) \[C{{H}_{3}}CH\,N{{O}_{2}}\,\xrightarrow{HN{{O}_{2}}}\,\underset{\begin{smallmatrix} \\ preudonitrol\,\,(blue) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ N=O \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-N{{O}_{2}}}}\,\] \[\xrightarrow{NaOH}\,\] No reaction blue (c)\[{{(C{{H}_{3}})}_{3}}CN{{O}_{2}}\xrightarrow{HN{{O}_{2}}}\]No reaction
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