A) \[C{{H}_{3}}C{{H}_{2}}CONHC{{H}_{3}}\]
B) \[C{{H}_{3}}CON{{(C{{H}_{2}}C{{H}_{2}}C{{H}_{3}})}_{2}}\]
C) \[C{{H}_{3}}CONHC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
D) \[C{{H}_{3}}CH=NC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: C
Solution :
\[\underset{N-propylacetamide.}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-NHC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\]
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